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Trigonometry

Verify cot x times sin x Equals cos x

Learn how to prove the identity cot x times sin x equals cos x by rewriting cotangent as cos x over sin x and canceling common factors.

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Problem

Verify the trigonometric identity

cotxsinx=cosx.\cot x \cdot \sin x = \cos x.

Step 1: Understand the Goal

We need to show that the left-hand side of the equation is equal to the right-hand side.

The identity is:

cotxsinx=cosx.\cot x \cdot \sin x = \cos x.

To verify it, we start with the left-hand side:

cotxsinx.\cot x \cdot \sin x.

Step 2: Use the Quotient Identity

We use the quotient identity for cotangent:

cotx=cosxsinx.\cot x = \frac{\cos x}{\sin x}.

Substitute this into the left-hand side:

cotxsinx=cosxsinxsinx.\cot x \cdot \sin x = \frac{\cos x}{\sin x} \cdot \sin x.

Step 3: Cancel the Common Factor

Now simplify:

cosxsinxsinx.\frac{\cos x}{\sin x} \cdot \sin x.

The factor sinx\sin x appears in the denominator and is also being multiplied, so it cancels:

cosxsinxsinx=cosx.\frac{\cos x}{\sin x} \cdot \sin x = \cos x.

Step 4: Final Answer

After simplifying the left-hand side, we get:

cosx.\cos x.

This matches the right-hand side of the original identity:

cotxsinx=cosx.\cot x \cdot \sin x = \cos x.

Therefore, the identity is verified.

Concepts

Trigonometric Ratios

The three basic trigonometric ratios -- sine, cosine, and tangent -- defined using the sides of a right triangle relative to a given acute angle. Used to find unknown side lengths or acute angle measures in right triangles. Applies only to acute angles in right triangles.

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