Cuestionario de series de Taylor con respuestas (Polinomios, R.C., Error)

Question 1

Halla la serie de Maclaurin de $\ln(1+x)$ (como serie de potencias).

Accepted Answer

$\displaystyle \sum_{n=0}^{\infty} (-1)^n \frac{x^{n+1}}{n+1}$

Answer

$\displaystyle \sum_{n=0}^{\infty} (-1)^n \frac{x^n}{n+1}$

Answer

$\displaystyle \sum_{n=1}^{\infty} \frac{x^n}{n}$

Answer

$\displaystyle \sum_{n=1}^{\infty} (-1)^{n+1} \frac{x^{n-1}}{n}$

Question 2

Halla la serie de Maclaurin de $\arctan x$.

Accepted Answer

$\displaystyle \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n+1}}{2n+1}$

Answer

$\displaystyle \sum_{n=1}^{\infty} (-1)^n \frac{x^{2n+1}}{2n+1}$

Answer

$\displaystyle \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n}}{2n+1}$

Answer

$\displaystyle \sum_{n=0}^{\infty} \frac{x^{2n+1}}{2n+1}$

Question 3

Usa el teorema de Taylor para acotar el error al aproximar $\ln(1.2)$ con el polinomio de Maclaurin de grado 3 de $\ln(1+x)$ (es decir, en $x=0.2$).

Accepted Answer

$\displaystyle |R_3(0.2)| \le \frac{6(0.2)^4}{4!}$

Answer

$\displaystyle |R_3(0.2)| \le \frac{(0.2)^4}{4}$

Answer

$\displaystyle |R_3(0.2)| \le \frac{(0.2)^3}{3!}$

Answer

$\displaystyle |R_3(0.2)| \le \frac{6(0.2)^4}{3!}$

Confianza y Reconocimiento